Men Grinch Onesie, Gaseous ethane (CH3CH3) will react with gaseous oxygen .. About featured snippets•FeedbackQuestions & answersCheggQuestionGaseous ethane (CH3CH3) reacts with gaseous oxygen gas (O2) toproduce gaseous carbon dioxide (CO2) and gaseous water (H2O). If0.179 of water is produced from the reaction of 0.90g of ethane and1.0g of oxygen gas, calculate the percent yield of water. Roundyour answer to 2 significant figures.Answer · 0 votesMoles calculation: Mole= The molar mass of ethane is 30.07 g/mol and is 31.998 g/molMoreWyzantQuestionGaseous ethane (CH3CH3) will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO2) and gaseous water (H2O)Answer · 0 votesWhenever you are given the amounts of both reactants, the first thing (after balancing the equation) is to find which reactant is limiting. CH3CH3 + 3O2 ==> 2CO2 + 2H2O . balanced equationTo find the limiting reactant, one way is to simply divide moles of each by the corresponding coefficient in the balanced equation. For CH3CH3 we have 27.4 g x 1 mol / 30 g = 0.913 mol CH3CH3 (÷1->0.9) For O2 we have 42. g O2 x 1 mol / 32 g = 1.31 mol O2 (÷3->0.4)Since 0.4 is less than 0.9, O2 is the limiting reactant, and we use the moles of O2 to find the theoretical yieldTheoretical yield of H2O = 1.31 mol O2 x 2 mol H2O / 3 mol O2 x 18 g H2O/mol = 15.7g H2O Theoretical yield of H2O = 16. g H2O (2 sig. figs. based on the value of 42. g O2)MoreBrainlyQuestionGaseous ethane (CH3CH3) reacts with gaseous oxygen gas (O2) to produce gaseous carbon dioxide (CO2) and gaseous water (H2O). If 2.71 g of carbon dioxide is produced from the reaction of 3.31 g of ethane and 23.9 g of oxygen gas, calculate the percent yield of carbon dioxide.Answer · 3 votesAnswer:The percent yield is 28.0 %Explanation:Step 1: Data givenMass of carbon dioxide = 2.71 gramsMass of ethane = 3.31 grams Mass of oxygen = 23.9 gramsMolar mass ethane = 30.07 g/molMolar mass CO2 = 44.01 g/molMolar mass O2 = 32.0 g/molStep 2: The balanced equation2C2H6 + 7O2 → 4CO2 + 6H2OStep 3: Calculate moles Moles = mass /molar massMoles ethane = 3.31 grams / 30.07 g/molMoles ethane = 0.110 molesMoles oxygen = 23.9 grams / 32.0 g/molMoles oxygen = 0.747 molesStep 4: Calculate the limiting reactantFor 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2OEthane is the limiting reactant. It will completely be consumed (0.110 moles)Oxygen is the limiting reactant. There will react 0.110 *3.5 = 0.385 molesThere will remain 0.747 - 0.385 = 0.362 moles O2Step 5: Calculate moles CO2For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2OFor 0.110 moles ethane we'll have 2*0.110 = 0.220 moles CO2Step 6: Calculate theoretical yield of CO2Mass CO2 = m…MoreStudy.comQuestionGaseous ethane (CH_3 CH_3) reacts with gaseous oxygen gas (O_2) to produce gaseous carbon dioxide.Answer · 0 votesThe first thing to do is write a balanced reaction:2CH3CH3+5O2→4CO2+6H2OWe will calculate the theoretical yield for each reactant mass assuming that that reactant is the limiting reactant, that is, assuming it is the reactant that reacts completely. The reactant that results in the smaller amount of product formed is the true limiting reactant, and that result is therefore the theoretical yield:AssumingCH3CH3islimiting:22.55gCH3CH3×1molCH3CH330.00gCH3CH3×4molCO22molCH3CH3×44.01gCO21molCO2=66.2gCO2AssumingO2islimiting:163.0gO2×1molO232.00gO2×4molCO25molO2×44.01gCO21molCO2=179.3gCO2The complete reaction of ethane results in the lesser amount of carbon dioxide produced. Therefore ethane is the limiting reactant. We expect 66.2 g of carbon dioxide to be produced from the reaction. We actually produce 50.8 g of carbon dioxide. So the %yield is:%yield=actualyieldtheoreticalyield×100%=50.8g66.2g×100%=76.7%MoreStudy.comQuestionGaseous ethane CH_3CH_3 reacts with gaseous oxygen gas O_2 to produce gaseous carbon dioxide CO_2.Answer · 0 votesGiven Data:• The mass of ethane is 21.0 g.• The mass of oxygen is 55.7 g.• The actual mass of water is 11.0 g.The chemical reaction is shown below.2C2H6(l)+7O2(g)→4CO2(g)+6H2O(g)The molar mass of ethane is 30.07 g/mol.The moles of ethane can be calculated as shown below.Numberofmoles=MassMolarmassSubstitute the respective values in the above equation.Numberofmoles=21.0g30.07g/mol=0.698molThe molar mass of oxygen is 32 g/mol.Similarly, the moles of oxygen can be calculated by substituting the respective values in the above equation.Numberofmoles=55.7g32g/mol=1.74molThe stoichiometric coefficient of ethane is 2 and oxygen is 7.For ethane:Numberofmoles=0.698mol2=0.349molFor oxygen:Numberofmoles=1.74mol7=0.248molThe moles of oxygen is less. So, the limiting reagent is oxygen.According to the above reaction, 7 moles of oxygen gives 6 moles of water.So, the moles of water are 67×1.74mol=1.49mol.The molar mass of water is 18 g/mol.The mass of water i…MoreAssignment ExpertQuestionGaseous ethane CH3CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 0.601 g of ethane is mixed with 1.7 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to 2 significant digits.Answer · 0 votes2CH3CH3 + 7O2 ----> 4CO2 + 6H2OMoles of ethane = 0.601/30= 0.020 molMoles of O2 = 1.7/32= 0.053 molO2 is limiting reagent.Mass of CO2 produced = 4×44×1.7/7×32= 1.3 gMass of carbondioxide = [1.3] gMoreNumeradeQuestionGaseous ethane CH3CH3 reacts with gaseous oxygen gas O2 toproduce gaseous carbon dioxide CO2 and gaseous water H2O. If 2.06gof carbon dioxide is produced from the reaction of 1.8g of ethaneand 3.8g of oxygen gas, calculate the percent yield of carbondioxide. Round your answer to 2 significant figures.Answer · 2 votesFirst, we'll need a balance chemical reaction, so we've got ethan, which is c 2 h, 6, reacting with oxygen gas to produce carbon dioxide and gaseous water. To balance it we need 2 carbon dioxide with the 2 carbons and 3 waters. So we get 6 hydrogen that then gives us 4 plus 3- that's 7 oxygen. So if we multiply this by 7 halves, that will give us a balanced reaction, but we want to get rid of that fraction. So we'll multiply everything through by 2, when we do that, then this becomes our balanced chemical reaction, where we now have 4 carbons: 4 carbons: 12 hydrogen 12 hydrogen 14 oxygen and we've got 6 plus 8, which is 14 point. So if we have 2.06 g of carbon dioxide produced from 1.8 g ethan and 3.8 g oxygen, we can calculate the theoretical yield for each of these reactants by converting into moles. First 1 mole than c 2 h. 6 has a molar mass equal to the mass of 2 moles carbon and 6 moles of hydrogen that being 30.069 grams. Then we recognize that 2 moles ethan yield 4 moles carbon…MoreCliffsNotesQuestionGaseous ethane (CH3CH3) will react with gaseous oxygen (02) to.Answer · 0 votesThe answer is followingMoreBartleby.comQuestionGaseous ethane (CH3CH3) reacts with gaseous oxygen gas (O2) to produce gaseous carbon dioxide (CO2) and gaseous water (H2O). If 1.61g of carbon dioxide is produced from the reaction of 2.7g of ethane and 3.1g of oxygen gas, calculate the percent yield of carbon dioxide.Be sure your answer has the correct number of significant digits in it.Answer · 0 votesStep 1 .MoreJustAnswerQuestionGaseous ethane reacts with gaseous oxygen gas to produce…Answer · 1 voteWe again start by writing the balanced equation: 2C2H6 + 7O2 -> 4CO2 + 6H2OThe molar mass of C2H6 is 30.1 g/mol, so 19.8 g is 0.658 mol C2H6The molar mass of O2 is 32.0 g/mol, so 54.7 g is 1.71 mol O2The limiting reagens is O2, so we can produce at most 1.71 / 7 * 4 = 0.977 molCO2The molar mass of CO2 is 44.0 g/mol, so we can produce at most 0.977*44.0 = 43.0g CO2This means the percent yield is 18.9/43.0 = 44.0%Best regards,TomMoreBartleby.comQuestionGaseous ethane CH3CH3 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. What is the theoretical yield of water formed from the reaction of 0.90g of ethane and 4.2g of oxygen gas?Be sure your answer has the correct number of significant digits in it!!Answer · 0 votesMoles of ethane and Oxygen are calculated .MoreQuoraQuestionGaseous ethane CH3CH3 reacts with gaseous oxygen O2 producing gaseous CO2 and gaseous H2O. Suppose 11.4 g of ethane is mixed with 31 g of oxygen, what is the minimum mass of ethane that could be left over by the chemical reaction?Answer · 1 voteWell, for starters we need a stoichiometrically balanced equation to represent the combustion of ethane…[math]H_{3}CCH_{3}(g) + frac{7}{2}O_{2}(g)ightarrow 2CO_{2}(g) + 3H_{2}O(l) + Delta[/math][math]text{Moles of ethane}=dfrac{11.4}{30.07•g•mol^{-1}}=0.379•mol[/math].[math]text{Moles of dioxygen}=dfrac{31.0}{32.00•g•mol^{-1}}=0.969•mol[/math].And given these molar quantities, CLEARLY, dioxygen is stoichiometric deficiency…complete combustion requires [math]1.33•mol[/math] with respect to dioxygen…but this problem is not one I would set with the given parameters, because we might invoke INCOMPLETE combustion, i.e. the presence of [math]CO(g)[/math] and particulate [math]C(s)[/math] as soot as OXIDATION products, but we have no way of assessing how complete this oxidation is WITHOUT experimental data… Of course, you could assume that the given quantity of dioxygen caused a stoichiometric quantity of ethane to combust completely, but this is not something that we could rea…MoreStudocuQuestionWrite a balanced equation to show the reaction of gaseous ethane with gaseous oxygen toform carbon monoxide gas and water vapor.A. 2 C2H6(g) + 7 O2(g)  4 CO2(g) + 6 H2O(g)B. 2 C2H6(g) + 5 O2(g)  4 CO(g) + 6H2O(g)C. C2H6(g) + 5 O(g)  2 CO(g) + 3 H2O(g)D. 2 CH3(g) + 5 O(g)  2 CO(g) + 3 H2O(g)E. C2H6(g) + 7 O(g)  2 CO2(g) + H2O(g)Answer · 0 votesThe correct answer is option B. A. The chemical formula of ethane and gaseous oxygen is C₂H₆ and O₂. The chemical formula of carbon monoxide and water is CO and H₂O. The given chemical equation is as follows - 2 C₂H₆ (g) + 7 O₂(g) → 4 CO₂ (g) + 6 H₂O (g) Here, the mentioned product is carbon dioxide (CO₂) instead of carbon monoxide (CO). Therefore, option A is incorrect. B. The given chemical equation is as follows - 2 C₂H₆ (g) + 5 O₂ (g) → 4 CO(g) + 6 H₂O (g) The number of C, O, and H atoms on both sides of the equation are 4, 10, and 12, respectively. Thus, the given equation is balanced. Therefore, option B is the correct answer. C. The formula of gaseous oxygen is O₂. The given chemical reaction is incorrect as the elemental O is used in place of gaseous oxygen (O₂). Therefore, option C is incorrect. D. The formula of ethane is C₂H₆ and not CH₃. Thus, option D is incorrect. E. In the case of the given chemical equation, the reactants are gaseous ethane (C₂H₆) and elemental O and th…MoreCourse HeroQuestionGaseous ethane (CH3CH3) will react with gaseous oxygen (O2) to.Answer · 0 votesC 2 H 6 + 7/2 0 2 ---------> 2CO 2 + 3H 2 0 27 g + 166g no.of moles = mass / molecular weight Molecular weight ; C 2 H 6 = 30 g/mole O 2 = 32 g/mole so, moles of C2H6 = 0.9 mole moles of O2 = 5.18 mole limiting reagent,for C2H6 = O.9 / 1 =0.9 mole O2 = 5.18 / 3.5 = 1.48 Therefore, C 2 H 6 is the limiting reagent. For stoichiometry , 7/2 mole of O 2 required 1 mole of C2H6 5.18 moles of O 2 requires 5.18 / (7/2) moles of C 2 H 6 =1.48 moles Moles of C2H6 remaining =(1.48 - 0.9) = 0.58 moles Therefore,' moles of C 2 H 6 remaining = (0.58 moles x 30 g/mole) =17.4 grams Mass of C2H6 remaining =17.4 gramsMoreTopprQuestionChemical equation for the reaction between ethane gas and oxygen is given below: 2C2H6 + 7O2→ 4CO2 + 6H2O (a) How many moles of ethane should react to form 20 mole CO2 (b) How many molecules are present in 67.2L ethane at STP?Answer · 6 votes(a) 2 moles of C2H6≡ 4 moles of CO2 ? ≡ 20 moles of CO2 By cross multiplication,Number of moles of C2H6 = 10 (b) 67.2/22.4 = 3 moles 3 × 6.022 × 10^23 = 18.066 × 10^23 molecules.More Feedback VideosYou will see more English now.7:31Gaseous ethane will react with gaseous oxygen to produce .YouTube · Not Your Chem Tutor7 minutes, 31 secondsFeb 2, 20238 key moments in this video3:11Balancing Ethane + Oxygen gasYouTube · MagnetsAndMotors (Dr. B's Other Channel)3 minutes, 11 secondsDec 12, 20197 key moments in this video2:09Complete Combustion of Ethane (C2H6) Balanced EquationYouTube · chemistNATE2 minutes, 9 secondsAug 30, 20194 key moments in this videoFeedbackView all Mens 3x Onesie, Gaseous ethane (CH3CH3) reacts with gaseous oxygen .. Mar 10, 2020 — Gaseous ethane (CH3CH3) reacts with gaseous oxygen gas (O2) to produce gaseous carbon dioxide (CO2) and gaseous water (H2O).1 answer  ·  Top answer: Answer:The percent yield is 28.0 %Explanation:Step 1: Data givenMass of carbon dioxide = 2.71 gramsMass of ethane = 3.31 grams Mass of oxygen = 23.9 gramsMolar . Mens Onesie With Butt Flap, Gaseous ethane CH_3CH_3 reacts with gaseous oxygen .. Answer to: Gaseous ethane CH_3CH_3 reacts with gaseous oxygen gas O_2 to produce gaseous carbon dioxide CO_2 and gaseous water H_2O . If 11.0 g of.1 answer  ·  Top answer: Given Data:• The mass of ethane is 21.0 g.• The mass of oxygen is 55.7 g.• The actual mass of water is 11.0 g.The chemical reaction . Mens Sherpa Onesie, Ethane C 2 H 6 reacts with oxygen gas to produce carbon .. Ethane(C2H6) reacts with oxygen gas to produce carbon dioxide and water. Initially, 5 mol of ethane is burned with 16 mol of oxygen, find the amount of carbon . Mens Thermal Onesie With Back Flap, Gaseous ethane CH3CH3 reacts with gaseous oxygen O2 .. Gaseous ethane CH3CH3 reacts with gaseous oxygen O2 producing gaseous CO2 and gaseous H2O. Suppose 11.4 g of ethane is mixed with 31 g of oxygen, .2 answers  ·  1 vote: Well, for starters we need a stoichiometrically balanced equation to represent the combustion . Mickey And Minnie Onesies, [ANSWERED] Gaseous ethane (CH3CH3) reacts with .. Aug 3, 2022 — Gaseous ethane (CH3CH3) reacts with gaseous oxygen gas (O₂) to produce gaseous carbon dioxide (CO₂) and gaseous water (H₂O). Minnie Onesie, Gaseous ethane CH3CH3 reacts with gaseous oxygen gas .. Nov 17, 2019 — Get the detailed answer: Gaseous ethane CH3CH3 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O . Monkey Onesie Costume, Chemical equation for the reaction between ethane gas .. Chemical equation for the reaction between ethane gas and oxygen is given below: 2C2​H6​+7O2​→4CO2​+6H2​O (a) How many moles of ethane should react to form .1 answer  ·  Top answer: (a) 2 moles of C2H6≡ 4 moles of CO2 ? ≡ 20 moles of CO2 By cross multiplication,Number of moles of C2H6 = 10 (b) 67.2/22.4 = 3 moles 3 × 6.022 × . Msu Onesie, Gaseous ethane (CH3CH3) will react with gaseous oxygen .. Gaseous ethane (CH3CH3) will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO2) and gaseous water (H2O). Suppose 27. g of ethane is .2 answers  ·  Top answer: C 2 H 6 + 7/2 0 2 ---------> 2CO 2 + 3H 2 0 27 g + 166g no.of moles = mass / molecular weight Molecular weight ; C 2 H 6 = 30 g/mole O 2 = 32 g/mole so, . Mummy Onesie, Highly Selective Oxidative Dehydrogenation of Ethane to .. Apr 28, 2022 — A chemical-looping-based oxidative dehydrogenation (CL-ODH) scheme is presented, in which oxygen carriers supply gaseous oxygen in situ, which . 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This is because, for every reaction, one or more bonds of a molecule must . Onesies Definition, Write balanced equations for the complete combustion of the .. Write the balanced equation for burning of natural gas When natural gas burns, . CH4 reacts with oxygen (O2) to make carbon dioxide (CO2) and water (H2O). Onesies On Sale, Kerala Syllabus 10th Standard Chemistry Solutions Chapter 2 .. May 1, 2023 — You can Download Gas Laws Mole Concept Questions and Answers, . How many moles of Oxygen is needed for the reaction with one mole of . Onesies Rue21, Selina solutions for Concise Chemistry Class 10 ICSE .. 24 cc Marsh gas (CH4) was mixed with 106 cc oxygen and then exploded. . volume of HCl gas formed and chlorine gas required when 40 ml of methane reacts . Panda Onesie For Teenager, Samacheer Kalvi 11th Chemistry Solutions Chapter 7 .. Apr 5, 2023 — ∆H for reaction 2Al + Cr2O3 → 2Cr + Al2O3 is … . When 15.68 litres of a gas mixture of methane and propane are fully combusted at 0°C . 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N2O is a colorless gas with a molecular weight of 44. Pook Onesie, C2h2cl2 hybridization. The molecule is made up of one Phosphorus atom, one oxygen atom, . 16 Feb C2H2 is a chemical formula for Ethyne, a gaseous alkyne hydrocarbon.